2008 Chevy Silverado V8 Four Wheel Drive Automatic 12000 miles
My '08 Silverado X-Cab has a OEM 145 Amp alternator and an AC Delco 7641 battery. I only have the single battery although there is space for an additional battery. How do I determine the maximum load with this OEM setup in watts? Is it simply by taking the max voltage (I believe it to be 15.5V @ 90% commanded duty cycle) and multiply it by the rated alternator max which is 145 Amps? That would give me 2,248 watts. Is that correct?
The reason I ask is I have 1000 watts RMS car audio in the truck and am looking at a Kinetik car audio battery to replace the AC Delco battery. Based on my calculations, I would need to take into account the 2,248 watts + 1,000 watts which means I need a battery that can handle 3,248 watts. Does that sound right?
have the same problem?
Sunday, June 7th, 2009 AT 6:18 PM